In the figure, BCDE is a parallelogram. DG, GH and BC are straight lines. BEF is an isosceles triangle.
- Find ∠d.
- Find ∠e.
(a)
∠DGB = ∠CBH = 66° (Corresponding angles, BC//GD)
∠GFB
= 180° - ∠DGB - ∠GBF
= 180° - 66° - 16°
= 98° (Angles sum of triangle)
∠EFB
= 180° - 98°
= 82° (Angles on a straight line)
∠FEB = ∠EFB = 82° (Isosceles triangle)
∠d
= ∠FEB
= 82° (Corresponding angles, CD//BE)
(b)
∠e
= 180° - 82° - 82°
= 16° (Isosceles triangle BEF)
Answer(s): (a) 82°; (b) 16°