In the figure, WXYZ is a parallelogram. YB, BC and WX are straight lines. WZA is an isosceles triangle.
- Find ∠t.
- Find ∠v.
(a)
∠YBW = ∠XWC = 61° (Corresponding angles, WX//BY)
∠BAW
= 180° - ∠YBW - ∠BWA
= 180° - 61° - 16°
= 103° (Angles sum of triangle)
∠ZAW
= 180° - 103°
= 77° (Angles on a straight line)
∠AZW = ∠ZAW = 77° (Isosceles triangle)
∠t
= ∠AZW
= 77° (Corresponding angles, XY//WZ)
(b)
∠v
= 180° - 77° - 77°
= 26° (Isosceles triangle WZA)
Answer(s): (a) 77°; (b) 26°
