In the figure, HJKL is a parallelogram. KN, NP and HJ are straight lines. HLM is an isosceles triangle.
- Find ∠t.
- Find ∠v.
(a)
∠KNH = ∠JHP = 58° (Corresponding angles, HJ//NK)
∠NMH
= 180° - ∠KNH - ∠NHM
= 180° - 58° - 21°
= 101° (Angles sum of triangle)
∠LMH
= 180° - 101°
= 79° (Angles on a straight line)
∠MLH = ∠LMH = 79° (Isosceles triangle)
∠t
= ∠MLH
= 79° (Corresponding angles, JK//HL)
(b)
∠v
= 180° - 79° - 79°
= 22° (Isosceles triangle HLM)
Answer(s): (a) 79°; (b) 22°