In the figure, BCDE is a parallelogram. DG, GH and BC are straight lines. BEF is an isosceles triangle.
- Find ∠t.
- Find ∠v.
(a)
∠DGB = ∠CBH = 62° (Corresponding angles, BC//GD)
∠GFB
= 180° - ∠DGB - ∠GBF
= 180° - 62° - 16°
= 102° (Angles sum of triangle)
∠EFB
= 180° - 102°
= 78° (Angles on a straight line)
∠FEB = ∠EFB = 78° (Isosceles triangle)
∠t
= ∠FEB
= 78° (Corresponding angles, CD//BE)
(b)
∠v
= 180° - 78° - 78°
= 24° (Isosceles triangle BEF)
Answer(s): (a) 78°; (b) 24°