In the figure, EFGH is a parallelogram. GK, KL and EF are straight lines. EHJ is an isosceles triangle.
- Find ∠s.
- Find ∠t.
(a)
∠GKE = ∠FEL = 58° (Corresponding angles, EF//KG)
∠KJE
= 180° - ∠GKE - ∠KEJ
= 180° - 58° - 16°
= 106° (Angles sum of triangle)
∠HJE
= 180° - 106°
= 74° (Angles on a straight line)
∠JHE = ∠HJE = 74° (Isosceles triangle)
∠s
= ∠JHE
= 74° (Corresponding angles, FG//EH)
(b)
∠t
= 180° - 74° - 74°
= 32° (Isosceles triangle EHJ)
Answer(s): (a) 74°; (b) 32°