In the figure, TUVW is a parallelogram. VY, YZ and TU are straight lines. TWX is an isosceles triangle.
- Find ∠j.
- Find ∠k.
(a)
∠VYT = ∠UTZ = 64° (Corresponding angles, TU//YV)
∠YXT
= 180° - ∠VYT - ∠YTX
= 180° - 64° - 21°
= 95° (Angles sum of triangle)
∠WXT
= 180° - 95°
= 85° (Angles on a straight line)
∠XWT = ∠WXT = 85° (Isosceles triangle)
∠j
= ∠XWT
= 85° (Corresponding angles, UV//TW)
(b)
∠k
= 180° - 85° - 85°
= 10° (Isosceles triangle TWX)
Answer(s): (a) 85°; (b) 10°