In the figure, TUVW is a parallelogram. VY, YZ and TU are straight lines. TWX is an isosceles triangle.
- Find ∠p.
- Find ∠q.
(a)
∠VYT = ∠UTZ = 61° (Corresponding angles, TU//YV)
∠YXT
= 180° - ∠VYT - ∠YTX
= 180° - 61° - 21°
= 98° (Angles sum of triangle)
∠WXT
= 180° - 98°
= 82° (Angles on a straight line)
∠XWT = ∠WXT = 82° (Isosceles triangle)
∠p
= ∠XWT
= 82° (Corresponding angles, UV//TW)
(b)
∠q
= 180° - 82° - 82°
= 16° (Isosceles triangle TWX)
Answer(s): (a) 82°; (b) 16°