In the figure, TUVW is a parallelogram. VY, YZ and TU are straight lines. TWX is an isosceles triangle.
- Find ∠p.
- Find ∠q.
(a)
∠VYT = ∠UTZ = 60° (Corresponding angles, TU//YV)
∠YXT
= 180° - ∠VYT - ∠YTX
= 180° - 60° - 21°
= 99° (Angles sum of triangle)
∠WXT
= 180° - 99°
= 81° (Angles on a straight line)
∠XWT = ∠WXT = 81° (Isosceles triangle)
∠p
= ∠XWT
= 81° (Corresponding angles, UV//TW)
(b)
∠q
= 180° - 81° - 81°
= 18° (Isosceles triangle TWX)
Answer(s): (a) 81°; (b) 18°