In the figure, EFGH is a parallelogram. GK, KL and EF are straight lines. EHJ is an isosceles triangle.
- Find ∠i.
- Find ∠j.
(a)
∠GKE = ∠FEL = 65° (Corresponding angles, EF//KG)
∠KJE
= 180° - ∠GKE - ∠KEJ
= 180° - 65° - 21°
= 94° (Angles sum of triangle)
∠HJE
= 180° - 94°
= 86° (Angles on a straight line)
∠JHE = ∠HJE = 86° (Isosceles triangle)
∠i
= ∠JHE
= 86° (Corresponding angles, FG//EH)
(b)
∠j
= 180° - 86° - 86°
= 8° (Isosceles triangle EHJ)
Answer(s): (a) 86°; (b) 8°