In the figure, JKLM is a parallelogram. LP, PQ and JK are straight lines. JMN is an isosceles triangle.
- Find ∠b.
- Find ∠c.
(a)
∠LPJ = ∠KJQ = 62° (Corresponding angles, JK//PL)
∠PNJ
= 180° - ∠LPJ - ∠PJN
= 180° - 62° - 15°
= 103° (Angles sum of triangle)
∠MNJ
= 180° - 103°
= 77° (Angles on a straight line)
∠NMJ = ∠MNJ = 77° (Isosceles triangle)
∠b
= ∠NMJ
= 77° (Corresponding angles, KL//JM)
(b)
∠c
= 180° - 77° - 77°
= 26° (Isosceles triangle JMN)
Answer(s): (a) 77°; (b) 26°
