In the figure, XYZA is a parallelogram. ZC, CD and XY are straight lines. XAB is an isosceles triangle.
- Find ∠h.
- Find ∠i.
(a)
∠ZCX = ∠YXD = 59° (Corresponding angles, XY//CZ)
∠CBX
= 180° - ∠ZCX - ∠CXB
= 180° - 59° - 21°
= 100° (Angles sum of triangle)
∠ABX
= 180° - 100°
= 80° (Angles on a straight line)
∠BAX = ∠ABX = 80° (Isosceles triangle)
∠h
= ∠BAX
= 80° (Corresponding angles, YZ//XA)
(b)
∠i
= 180° - 80° - 80°
= 20° (Isosceles triangle XAB)
Answer(s): (a) 80°; (b) 20°
