In the figure, ZABC is a parallelogram. BE, EF and ZA are straight lines. ZCD is an isosceles triangle.
- Find ∠h.
- Find ∠i.
(a)
∠BEZ = ∠AZF = 66° (Corresponding angles, ZA//EB)
∠EDZ
= 180° - ∠BEZ - ∠EZD
= 180° - 66° - 15°
= 99° (Angles sum of triangle)
∠CDZ
= 180° - 99°
= 81° (Angles on a straight line)
∠DCZ = ∠CDZ = 81° (Isosceles triangle)
∠h
= ∠DCZ
= 81° (Corresponding angles, AB//ZC)
(b)
∠i
= 180° - 81° - 81°
= 18° (Isosceles triangle ZCD)
Answer(s): (a) 81°; (b) 18°
