In the figure, HJKL is a parallelogram. KN, NP and HJ are straight lines. HLM is an isosceles triangle.
- Find ∠g.
- Find ∠h.
(a)
∠KNH = ∠JHP = 66° (Corresponding angles, HJ//NK)
∠NMH
= 180° - ∠KNH - ∠NHM
= 180° - 66° - 21°
= 93° (Angles sum of triangle)
∠LMH
= 180° - 93°
= 87° (Angles on a straight line)
∠MLH = ∠LMH = 87° (Isosceles triangle)
∠g
= ∠MLH
= 87° (Corresponding angles, JK//HL)
(b)
∠h
= 180° - 87° - 87°
= 6° (Isosceles triangle HLM)
Answer(s): (a) 87°; (b) 6°