In the figure, DEFG is a parallelogram. FJ, JK and DE are straight lines. DGH is an isosceles triangle.
- Find ∠j.
- Find ∠k.
(a)
∠FJD = ∠EDK = 66° (Corresponding angles, DE//JF)
∠JHD
= 180° - ∠FJD - ∠JDH
= 180° - 66° - 20°
= 94° (Angles sum of triangle)
∠GHD
= 180° - 94°
= 86° (Angles on a straight line)
∠HGD = ∠GHD = 86° (Isosceles triangle)
∠j
= ∠HGD
= 86° (Corresponding angles, EF//DG)
(b)
∠k
= 180° - 86° - 86°
= 8° (Isosceles triangle DGH)
Answer(s): (a) 86°; (b) 8°
