In the figure, ZABC is a parallelogram. BE, EF and ZA are straight lines. ZCD is an isosceles triangle.
- Find ∠b.
- Find ∠c.
(a)
∠BEZ = ∠AZF = 62° (Corresponding angles, ZA//EB)
∠EDZ
= 180° - ∠BEZ - ∠EZD
= 180° - 62° - 15°
= 103° (Angles sum of triangle)
∠CDZ
= 180° - 103°
= 77° (Angles on a straight line)
∠DCZ = ∠CDZ = 77° (Isosceles triangle)
∠b
= ∠DCZ
= 77° (Corresponding angles, AB//ZC)
(b)
∠c
= 180° - 77° - 77°
= 26° (Isosceles triangle ZCD)
Answer(s): (a) 77°; (b) 26°