In the figure, YZAB is a parallelogram. AD, DE and YZ are straight lines. YBC is an isosceles triangle.
- Find ∠v.
- Find ∠w.
(a)
∠ADY = ∠ZYE = 60° (Corresponding angles, YZ//DA)
∠DCY
= 180° - ∠ADY - ∠DYC
= 180° - 60° - 19°
= 101° (Angles sum of triangle)
∠BCY
= 180° - 101°
= 79° (Angles on a straight line)
∠CBY = ∠BCY = 79° (Isosceles triangle)
∠v
= ∠CBY
= 79° (Corresponding angles, ZA//YB)
(b)
∠w
= 180° - 79° - 79°
= 22° (Isosceles triangle YBC)
Answer(s): (a) 79°; (b) 22°