In the figure, HJKL is a parallelogram. KN, NP and HJ are straight lines. HLM is an isosceles triangle.
- Find ∠f.
- Find ∠g.
(a)
∠KNH = ∠JHP = 62° (Corresponding angles, HJ//NK)
∠NMH
= 180° - ∠KNH - ∠NHM
= 180° - 62° - 21°
= 97° (Angles sum of triangle)
∠LMH
= 180° - 97°
= 83° (Angles on a straight line)
∠MLH = ∠LMH = 83° (Isosceles triangle)
∠f
= ∠MLH
= 83° (Corresponding angles, JK//HL)
(b)
∠g
= 180° - 83° - 83°
= 14° (Isosceles triangle HLM)
Answer(s): (a) 83°; (b) 14°
