In the figure, ABCD is a parallelogram. CF, FG and AB are straight lines. ADE is an isosceles triangle.
- Find ∠j.
- Find ∠k.
(a)
∠CFA = ∠BAG = 65° (Corresponding angles, AB//FC)
∠FEA
= 180° - ∠CFA - ∠FAE
= 180° - 65° - 21°
= 94° (Angles sum of triangle)
∠DEA
= 180° - 94°
= 86° (Angles on a straight line)
∠EDA = ∠DEA = 86° (Isosceles triangle)
∠j
= ∠EDA
= 86° (Corresponding angles, BC//AD)
(b)
∠k
= 180° - 86° - 86°
= 8° (Isosceles triangle ADE)
Answer(s): (a) 86°; (b) 8°
