The figure is not drawn to scale. FGJK is a parallelogram. ∠KFO is 56° and ∠JGH is 24°. FGH is an isosceles triangle and FG = GH.
- Find ∠OHG.
- Find ∠FKJ.
(a)
∠GOF = 56° (Alternate angles, FK//GJ)
∠GOH
= 180° - 56°
= 124° (Angles on a straight line)
∠OHG
= 180° - 124° - 24°
= 32° (Angles sum of triangle)
(b)
∠GFO = 32° (Isosceles triangle FGH)
∠FKJ
= 180° - 56° - 32°
= 92° (Interior angles, FG//KJ)
Answer(s): (a) 32°; (b) 92°