The figure is not drawn to scale. VWYZ is a parallelogram. ∠ZVO is 56° and ∠YWX is 28°. VWX is an isosceles triangle and VW = WX.
- Find ∠OXW.
- Find ∠VZY.
(a)
∠WOV = 56° (Alternate angles, VZ//WY)
∠WOX
= 180° - 56°
= 124° (Angles on a straight line)
∠OXW
= 180° - 124° - 28°
= 28° (Angles sum of triangle)
(b)
∠WVO = 28° (Isosceles triangle VWX)
∠VZY
= 180° - 56° - 28°
= 96° (Interior angles, VW//ZY)
Answer(s): (a) 28°; (b) 96°