The figure is not drawn to scale. JKMN is a parallelogram. ∠NJO is 54° and ∠MKL is 28°. JKL is an isosceles triangle and JK = KL.
- Find ∠OLK.
- Find ∠JNM.
(a)
∠KOJ = 54° (Alternate angles, JN//KM)
∠KOL
= 180° - 54°
= 126° (Angles on a straight line)
∠OLK
= 180° - 126° - 28°
= 26° (Angles sum of triangle)
(b)
∠KJO = 26° (Isosceles triangle JKL)
∠JNM
= 180° - 54° - 26°
= 100° (Interior angles, JK//NM)
Answer(s): (a) 26°; (b) 100°