The figure is not drawn to scale. HJLM is a parallelogram. ∠MHO is 59° and ∠LJK is 27°. HJK is an isosceles triangle and HJ = JK.
- Find ∠OKJ.
- Find ∠HML.
(a)
∠JOH = 59° (Alternate angles, HM//JL)
∠JOK
= 180° - 59°
= 121° (Angles on a straight line)
∠OKJ
= 180° - 121° - 27°
= 32° (Angles sum of triangle)
(b)
∠JHO = 32° (Isosceles triangle HJK)
∠HML
= 180° - 59° - 32°
= 89° (Interior angles, HJ//ML)
Answer(s): (a) 32°; (b) 89°