The figure is not drawn to scale. VWYZ is a parallelogram. ∠ZVO is 59° and ∠YWX is 32°. VWX is an isosceles triangle and VW = WX.
- Find ∠OXW.
- Find ∠VZY.
(a)
∠WOV = 59° (Alternate angles, VZ//WY)
∠WOX
= 180° - 59°
= 121° (Angles on a straight line)
∠OXW
= 180° - 121° - 32°
= 27° (Angles sum of triangle)
(b)
∠WVO = 27° (Isosceles triangle VWX)
∠VZY
= 180° - 59° - 27°
= 94° (Interior angles, VW//ZY)
Answer(s): (a) 27°; (b) 94°