Question
P6.AN.NK.17051723-A1
The figure is not drawn to scale. EFHJ is a parallelogram. ∠JEO is 57° and ∠HFG is 25°. EFG is an isosceles triangle and EF = FG.
  1. Find ∠OGF.
  2. Find ∠EJH.
4 m
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Primary 6 ANGLES P6.AN.NK.17051723

02 Jun 2024, 02:43 AM

The figure is not drawn to scale. EFHJ is a parallelogram. ∠JEO is 57° and ∠HFG is 25°. EFG is an isosceles triangle and EF = FG.
  1. Find ∠OGF.
  2. Find ∠EJH.
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