The figure is not drawn to scale. HJLM is a parallelogram. ∠MHO is 54° and ∠LJK is 24°. HJK is an isosceles triangle and HJ = JK.
- Find ∠OKJ.
- Find ∠HML.
(a)
∠JOH = 54° (Alternate angles, HM//JL)
∠JOK
= 180° - 54°
= 126° (Angles on a straight line)
∠OKJ
= 180° - 126° - 24°
= 30° (Angles sum of triangle)
(b)
∠JHO = 30° (Isosceles triangle HJK)
∠HML
= 180° - 54° - 30°
= 96° (Interior angles, HJ//ML)
Answer(s): (a) 30°; (b) 96°