The figure is not drawn to scale. HJLM is a parallelogram. ∠MHO is 57° and ∠LJK is 29°. HJK is an isosceles triangle and HJ = JK.
- Find ∠OKJ.
- Find ∠HML.
(a)
∠JOH = 57° (Alternate angles, HM//JL)
∠JOK
= 180° - 57°
= 123° (Angles on a straight line)
∠OKJ
= 180° - 123° - 29°
= 28° (Angles sum of triangle)
(b)
∠JHO = 28° (Isosceles triangle HJK)
∠HML
= 180° - 57° - 28°
= 95° (Interior angles, HJ//ML)
Answer(s): (a) 28°; (b) 95°