The figure is not drawn to scale. VWYZ is a parallelogram. ∠ZVO is 55° and ∠YWX is 32°. VWX is an isosceles triangle and VW = WX.
- Find ∠OXW.
- Find ∠VZY.
(a)
∠WOV = 55° (Alternate angles, VZ//WY)
∠WOX
= 180° - 55°
= 125° (Angles on a straight line)
∠OXW
= 180° - 125° - 32°
= 23° (Angles sum of triangle)
(b)
∠WVO = 23° (Isosceles triangle VWX)
∠VZY
= 180° - 55° - 23°
= 102° (Interior angles, VW//ZY)
Answer(s): (a) 23°; (b) 102°