The figure is not drawn to scale. VWYZ is a parallelogram. ∠ZVO is 58° and ∠YWX is 26°. VWX is an isosceles triangle and VW = WX.
- Find ∠OXW.
- Find ∠VZY.
(a)
∠WOV = 58° (Alternate angles, VZ//WY)
∠WOX
= 180° - 58°
= 122° (Angles on a straight line)
∠OXW
= 180° - 122° - 26°
= 32° (Angles sum of triangle)
(b)
∠WVO = 32° (Isosceles triangle VWX)
∠VZY
= 180° - 58° - 32°
= 90° (Interior angles, VW//ZY)
Answer(s): (a) 32°; (b) 90°