The figure is not drawn to scale. FGJK is a parallelogram. ∠KFO is 55° and ∠JGH is 30°. FGH is an isosceles triangle and FG = GH.
- Find ∠OHG.
- Find ∠FKJ.
(a)
∠GOF = 55° (Alternate angles, FK//GJ)
∠GOH
= 180° - 55°
= 125° (Angles on a straight line)
∠OHG
= 180° - 125° - 30°
= 25° (Angles sum of triangle)
(b)
∠GFO = 25° (Isosceles triangle FGH)
∠FKJ
= 180° - 55° - 25°
= 100° (Interior angles, FG//KJ)
Answer(s): (a) 25°; (b) 100°