The figure is not drawn to scale. JKMN is a parallelogram. ∠NJO is 55° and ∠MKL is 30°. JKL is an isosceles triangle and JK = KL.
- Find ∠OLK.
- Find ∠JNM.
(a)
∠KOJ = 55° (Alternate angles, JN//KM)
∠KOL
= 180° - 55°
= 125° (Angles on a straight line)
∠OLK
= 180° - 125° - 30°
= 25° (Angles sum of triangle)
(b)
∠KJO = 25° (Isosceles triangle JKL)
∠JNM
= 180° - 55° - 25°
= 100° (Interior angles, JK//NM)
Answer(s): (a) 25°; (b) 100°