The figure is not drawn to scale. JKMN is a parallelogram. ∠NJO is 58° and ∠MKL is 24°. JKL is an isosceles triangle and JK = KL.
- Find ∠OLK.
- Find ∠JNM.
(a)
∠KOJ = 58° (Alternate angles, JN//KM)
∠KOL
= 180° - 58°
= 122° (Angles on a straight line)
∠OLK
= 180° - 122° - 24°
= 34° (Angles sum of triangle)
(b)
∠KJO = 34° (Isosceles triangle JKL)
∠JNM
= 180° - 58° - 34°
= 88° (Interior angles, JK//NM)
Answer(s): (a) 34°; (b) 88°