The figure is not drawn to scale. JKMN is a parallelogram. ∠NJO is 60° and ∠MKL is 31°. JKL is an isosceles triangle and JK = KL.
- Find ∠OLK.
- Find ∠JNM.
(a)
∠KOJ = 60° (Alternate angles, JN//KM)
∠KOL
= 180° - 60°
= 120° (Angles on a straight line)
∠OLK
= 180° - 120° - 31°
= 29° (Angles sum of triangle)
(b)
∠KJO = 29° (Isosceles triangle JKL)
∠JNM
= 180° - 60° - 29°
= 91° (Interior angles, JK//NM)
Answer(s): (a) 29°; (b) 91°