In the figure, XADG is a rectangle, DEGH is a rhombus and ABCD is a parallelogram. ∠DEG = 80° and ∠CDE = 94°.
- Find ∠ZDA
- Find ∠DCB
(a)
∠GHD = ∠GED = 80°
∠HDG
= (180° - 80°) ÷ 2
= 100° ÷ 2
= 50° (Isosceles triangle)
∠ZDA
= 90° - 50°
= 40°
(b)
∠ADC
= 360° - 94° - 90° - 50°
= 126° (Angles at a point)
∠BCD
= 180° - 126°
= 54° (Interior Angles, AD//BF)
Answer(s): (a) 40°; (b) 54°