In the figure, WZCF is a rectangle, CDFG is a rhombus and ZABC is a parallelogram. ∠CDF = 76° and ∠BCD = 94°.
- Find ∠YCZ
- Find ∠CBA
(a)
∠FGC = ∠FDC = 76°
∠GCF
= (180° - 76°) ÷ 2
= 104° ÷ 2
= 52° (Isosceles triangle)
∠YCZ
= 90° - 52°
= 38°
(b)
∠ZCB
= 360° - 94° - 90° - 52°
= 124° (Angles at a point)
∠ABC
= 180° - 124°
= 56° (Interior Angles, ZC//AF)
Answer(s): (a) 38°; (b) 56°