In the figure, ZCFJ is a rectangle, FGJK is a rhombus and CDEF is a parallelogram. ∠FGJ = 76° and ∠EFG = 91°.
- Find ∠BFC
- Find ∠FED
(a)
∠JKF = ∠JGF = 76°
∠KFJ
= (180° - 76°) ÷ 2
= 104° ÷ 2
= 52° (Isosceles triangle)
∠BFC
= 90° - 52°
= 38°
(b)
∠CFE
= 360° - 91° - 90° - 52°
= 127° (Angles at a point)
∠DEF
= 180° - 127°
= 53° (Interior Angles, CF//DF)
Answer(s): (a) 38°; (b) 53°