In the figure, BEHL is a rectangle, HJLM is a rhombus and EFGH is a parallelogram. ∠HJL = 80° and ∠GHJ = 91°.
- Find ∠DHE
- Find ∠HGF
(a)
∠LMH = ∠LJH = 80°
∠MHL
= (180° - 80°) ÷ 2
= 100° ÷ 2
= 50° (Isosceles triangle)
∠DHE
= 90° - 50°
= 40°
(b)
∠EHG
= 360° - 91° - 90° - 50°
= 129° (Angles at a point)
∠FGH
= 180° - 129°
= 51° (Interior Angles, EH//FF)
Answer(s): (a) 40°; (b) 51°