In the figure, CFJM is a rectangle, JKMN is a rhombus and FGHJ is a parallelogram. ∠JKM = 76° and ∠HJK = 91°.
- Find ∠EJF
- Find ∠JHG
(a)
∠MNJ = ∠MKJ = 76°
∠NJM
= (180° - 76°) ÷ 2
= 104° ÷ 2
= 52° (Isosceles triangle)
∠EJF
= 90° - 52°
= 38°
(b)
∠FJH
= 360° - 91° - 90° - 52°
= 127° (Angles at a point)
∠GHJ
= 180° - 127°
= 53° (Interior Angles, FJ//GF)
Answer(s): (a) 38°; (b) 53°