In the figure, WZCF is a rectangle, CDFG is a rhombus and ZABC is a parallelogram. ∠CDF = 80° and ∠BCD = 94°.
- Find ∠YCZ
- Find ∠CBA
(a)
∠FGC = ∠FDC = 80°
∠GCF
= (180° - 80°) ÷ 2
= 100° ÷ 2
= 50° (Isosceles triangle)
∠YCZ
= 90° - 50°
= 40°
(b)
∠ZCB
= 360° - 94° - 90° - 50°
= 126° (Angles at a point)
∠ABC
= 180° - 126°
= 54° (Interior Angles, ZC//AF)
Answer(s): (a) 40°; (b) 54°