In the figure, CFJM is a rectangle, JKMN is a rhombus and FGHJ is a parallelogram. ∠JKM = 74° and ∠HJK = 96°.
- Find ∠EJF
- Find ∠JHG
(a)
∠MNJ = ∠MKJ = 74°
∠NJM
= (180° - 74°) ÷ 2
= 106° ÷ 2
= 53° (Isosceles triangle)
∠EJF
= 90° - 53°
= 37°
(b)
∠FJH
= 360° - 96° - 90° - 53°
= 121° (Angles at a point)
∠GHJ
= 180° - 121°
= 59° (Interior Angles, FJ//GF)
Answer(s): (a) 37°; (b) 59°