The figure is not drawn to scale. ZCEJ is a parallelogram. BFH and ADG are triangles. ∠BFG = 79° and GAD = 53°. Find
- ∠ABF
- the sum of ∠AGD, ∠BXD and ∠DYF.
(a)
∠ABF
= 180° - 79°
= 101° (Interior angles, ZC//JE)
(b)
∠BXD = ∠AXY (Vertically opposite angles)
∠DYF = ∠GYX (Vertically opposite angles)
AGYX is a quadrilateral.
∠AGD + ∠GYX + ∠AXY + 53° = 360° (Sum of angles in a quadrilateral)
∠AGD + ∠GYX + ∠AXY
= 360° - 53°
= 307°
Answer(s): (a) 101°; (b) 307°