The figure is not drawn to scale. EHKP is a parallelogram. GLN and FJM are triangles. ∠GLM = 80° and MFJ = 50°. Find
- ∠FGL
- the sum of ∠FMJ, ∠GCJ and ∠JDL.
(a)
∠FGL
= 180° - 80°
= 100° (Interior angles, EH//PK)
(b)
∠GCJ = ∠FCD (Vertically opposite angles)
∠JDL = ∠MDC (Vertically opposite angles)
FMDC is a quadrilateral.
∠FMJ + ∠MDC + ∠FCD + 50° = 360° (Sum of angles in a quadrilateral)
∠FMJ + ∠MDC + ∠FCD
= 360° - 50°
= 310°
Answer(s): (a) 100°; (b) 310°