The figure is not drawn to scale. UXZD is a parallelogram. WAC and VYB are triangles. ∠WAB = 82° and BVY = 56°. Find
- ∠VWA
- the sum of ∠VBY, ∠WSY and ∠YTA.
(a)
∠VWA
= 180° - 82°
= 98° (Interior angles, UX//DZ)
(b)
∠WSY = ∠VST (Vertically opposite angles)
∠YTA = ∠BTS (Vertically opposite angles)
VBTS is a quadrilateral.
∠VBY + ∠BTS + ∠VST + 56° = 360° (Sum of angles in a quadrilateral)
∠VBY + ∠BTS + ∠VST
= 360° - 56°
= 304°
Answer(s): (a) 98°; (b) 304°