The figure is not drawn to scale. XACG is a parallelogram. ZDF and YBE are triangles. ∠ZDE = 80° and EYB = 55°. Find
- ∠YZD
- the sum of ∠YEB, ∠ZVB and ∠BWD.
(a)
∠YZD
= 180° - 80°
= 100° (Interior angles, XA//GC)
(b)
∠ZVB = ∠YVW (Vertically opposite angles)
∠BWD = ∠EWV (Vertically opposite angles)
YEWV is a quadrilateral.
∠YEB + ∠EWV + ∠YVW + 55° = 360° (Sum of angles in a quadrilateral)
∠YEB + ∠EWV + ∠YVW
= 360° - 55°
= 305°
Answer(s): (a) 100°; (b) 305°