The figure is not drawn to scale. ∠HGJ = 41°, HG = HJ and GM//HL. Given that ∠y is
13 of ∠w and ∠y is 4 times of ∠x, find
- ∠y
- ∠v
(a)
y : w = 1 : 3
w = 3 y
x : y = 1 : 4
w = 3 x 4= 12
w : x : y = 12 : 1 : 4
∠HJG = 41° (Isosceles triangle)
∠GJK
= 180° - 41°
= 139° (Angles on a straight line)
1 u + 4 u + 12 u + 139° = 360° (Sum of angles in a quadrilateral)
17 u = 360° - 139° = 221°
1 u = 221 ÷ 17 = 13°
∠y
= 4 x 1 u
= 4 x 13°
= 52°
(b)
∠HJG = ∠HGJ = 41° (Isosceles triangle)
∠JNL = ∠JGM = 52° (Corresponding angles, GM//HL)
∠v
= 52° - 41°
= 11° (Exterior angle of a triangle)
Answer(s): (a) 52°; (b) 11°
