The figure, not drawn to scale, O is the centre of the circle and HN // JM // KL. Find
- ∠GOK
- ∠GMO
(a)
∠NOJ
= 180° - 98°
= 82° (Interior angles, HN//JO)
∠OKM = ∠OMK = 32° (Isosceles triangle)
∠JOK
= 32° + 32°
= 64° (Exterior angle of a triangle)
∠GOK
= 82° + 64°
= 146°
(b)
∠MOK
= 180° - 32° -32°
= 116° (Isosceles triangle)
∠GOM
= 360° - 146° - 116°
= 98° (Angles at a point)
GO = OM = Radius
∠GMO
= (180° - 98°) ÷ 2
= 82° ÷ 2
= 41° (Isosceles triangle)
Answer(s): (a) 146°; (b) 41°