The figure, not drawn to scale, O is the centre of the circle and MS // NR // PQ. Find
- ∠LOP
- ∠LRO
(a)
∠SON
= 180° - 98°
= 82° (Interior angles, MS//NO)
∠OPR = ∠ORP = 30° (Isosceles triangle)
∠NOP
= 30° + 30°
= 60° (Exterior angle of a triangle)
∠LOP
= 82° + 60°
= 142°
(b)
∠ROP
= 180° - 30° -30°
= 120° (Isosceles triangle)
∠LOR
= 360° - 142° - 120°
= 98° (Angles at a point)
LO = OR = Radius
∠LRO
= (180° - 98°) ÷ 2
= 82° ÷ 2
= 41° (Isosceles triangle)
Answer(s): (a) 142°; (b) 41°
