The figure, not drawn to scale, O is the centre of the circle and GM // HL // JK. Find
- ∠FOJ
- ∠FLO
(a)
∠MOH
= 180° - 98°
= 82° (Interior angles, GM//HO)
∠OJL = ∠OLJ = 28° (Isosceles triangle)
∠HOJ
= 28° + 28°
= 56° (Exterior angle of a triangle)
∠FOJ
= 82° + 56°
= 138°
(b)
∠LOJ
= 180° - 28° -28°
= 124° (Isosceles triangle)
∠FOL
= 360° - 138° - 124°
= 98° (Angles at a point)
FO = OL = Radius
∠FLO
= (180° - 98°) ÷ 2
= 82° ÷ 2
= 41° (Isosceles triangle)
Answer(s): (a) 138°; (b) 41°