The figure, not drawn to scale, O is the centre of the circle and HN // JM // KL. Find
- ∠GOK
- ∠GMO
(a)
∠NOJ
= 180° - 96°
= 84° (Interior angles, HN//JO)
∠OKM = ∠OMK = 30° (Isosceles triangle)
∠JOK
= 30° + 30°
= 60° (Exterior angle of a triangle)
∠GOK
= 84° + 60°
= 144°
(b)
∠MOK
= 180° - 30° -30°
= 120° (Isosceles triangle)
∠GOM
= 360° - 144° - 120°
= 96° (Angles at a point)
GO = OM = Radius
∠GMO
= (180° - 96°) ÷ 2
= 84° ÷ 2
= 42° (Isosceles triangle)
Answer(s): (a) 144°; (b) 42°
