The figure, not drawn to scale, O is the centre of the circle and HN // JM // KL. Find
- ∠GOK
- ∠GMO
(a)
∠NOJ
= 180° - 98°
= 82° (Interior angles, HN//JO)
∠OKM = ∠OMK = 29° (Isosceles triangle)
∠JOK
= 29° + 29°
= 58° (Exterior angle of a triangle)
∠GOK
= 82° + 58°
= 140°
(b)
∠MOK
= 180° - 29° -29°
= 122° (Isosceles triangle)
∠GOM
= 360° - 140° - 122°
= 98° (Angles at a point)
GO = OM = Radius
∠GMO
= (180° - 98°) ÷ 2
= 82° ÷ 2
= 41° (Isosceles triangle)
Answer(s): (a) 140°; (b) 41°