The figure, not drawn to scale, O is the centre of the circle and RW // SV // TU. Find
- ∠QOT
- ∠QVO
(a)
∠WOS
= 180° - 100°
= 80° (Interior angles, RW//SO)
∠OTV = ∠OVT = 32° (Isosceles triangle)
∠SOT
= 32° + 32°
= 64° (Exterior angle of a triangle)
∠QOT
= 80° + 64°
= 144°
(b)
∠VOT
= 180° - 32° -32°
= 116° (Isosceles triangle)
∠QOV
= 360° - 144° - 116°
= 100° (Angles at a point)
QO = OV = Radius
∠QVO
= (180° - 100°) ÷ 2
= 80° ÷ 2
= 40° (Isosceles triangle)
Answer(s): (a) 144°; (b) 40°